继续创造，加快成长！这是我参加「掘金日新方案 10 月更文应战」的第17天，点击查看活动概况
[UTCTF2020]OTP
下载附件得到一些很古怪的东西：
Encoded A: 213c234c2322282057730b32492e720b35732b2124553d354c22352224237f1826283d7b0651
Encoded B: 3b3b463829225b3632630b542623767f39674431343b353435412223243b7f162028397a103e
Original A: 5448452042455354204354462043415445474f52592049532043525950544f47524150485921
Original B: 4e4f205448452042455354204f4e452049532042494e415259204558504c4f49544154494f4e
A XOR A: 7574666c61677b7477305f74696d335f703464737d7574666c61677b7477305f74696d335f70
B XOR B: 7574666c61677b7477305f74696d335f703464737d7574666c61677b7477305f74696d335f70
搞不懂这些字符串是什么意思，网上了解一下：发现是一个名叫One Time Pad的问题。
A XOR A是最终的加密结果，对其进行hex解码：
utflag{tw0_tim3_p4ds}
太菜了，没太搞懂这题考的什么意思，还是得多学习啊。
[BJDCTF2020]宓羲六十四
下载附件得到密文：
密文:升随临损巽睽颐萃小过讼艮颐小过震蛊屯未济中孚艮困恒晋升损蛊萃蛊未济巽解艮贲未济观豫损蛊晋噬嗑晋旅解大畜困未济随蒙升解睽未济井困未济旅萃未济震蒙未济师涣归妹大有
搞不懂啥意思，附加内容还有个b=7，不知道有什么用。
还有一个python文件：
# -- coding:UTF-8 --
from secret import flag
def encrpyt5():
enc=''
for i in flag:
enc+=chr((a*(ord(i)-97)+b)%26+97)
return(enc)
def encrypt4():
temp=''
offset=5
for i in range(len(enc)):
temp+=chr(ord(enc[i])-offset-i)
return(temp)
找一个脚本解一下：
s='升随临损巽睽颐萃小过讼艮颐小过震蛊屯未济中孚艮困恒晋升损蛊萃蛊未济巽解艮贲未济观豫损蛊晋噬嗑晋旅解大畜困未济随蒙升解睽未济井困未济旅萃未济震蒙未济师涣归妹大有'
dic={'坤': '000000', '剥': '000001', '比': '000010', '观': '000011', '豫': '000100', '晋': '000101', '萃': '000110', '否': '000111', '谦': '001000', '艮': '001001', '蹇': '001010', '渐': '001011', '小过': '001100', '旅': '001101', '咸': '001110', '遁': '001111', '师': '010000', '蒙': '010001', '坎': '010010', '涣': '010011', '解': '010100', '未济': '010101', '困': '010110', '讼': '010111', '升': '011000', '蛊': '011001', '井': '011010', '巽': '011011', '恒': '011100', '鼎': '011101', '大过': '011110', '姤': '011111', '复': '100000', '颐': '100001', '屯': '100010', '益': '100011', '震': '100100', '噬嗑': '100101', '随': '100110', '无妄': '100111', '明夷': '101000', '贲': '101001', '既济': '101010', '家人': '101011', '丰': '101100', '离': '101101', '革': '101110', '同人': '101111', '临': '110000', '损': '110001', '节': '110010', '中孚': '110011', '归妹': '110100', '睽': '110101', '兑': '110110', '履': '110111', '泰': '111000', '大畜': '111001', '需': '111010', '小畜': '111011', '大壮': '111100', '大有': '111101', '夬': '111110', '乾': '111111'}
li=[]
k=0
for i in range(len(s)):
if k ==1:
k=0
continue
try:
li.append(dic[s[i]])
except:
t=''
t=t+s[i]+s[i+1]
li.append(dic[t])
k=1
ss=''.join(li)
print(ss)
enc=''
for i in range(0,len(ss),8):
enc+=chr(eval('0b'+ss[i:i+8]))
print(enc)
运行得到base64编码，解码得到：
n]h]kka[[eiWW_R`bO]]`NMUWWIFXHUCP
经过两层解密，得到flag:
bjd{bjdcongratulationsongettingtheflag}
[NCTF2019]Sore
下载附件得到txt文件内容如下：
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
维吉尼亚解密得到字符串：
vlbeunuozbpycklsjxlfpaq
咱们回到附件的python文件：
from string import ascii_letters
from flag import flag
ctoi = lambda x: ascii_letters.index(x)
itoc = lambda x: ascii_letters[x]
key = flag.strip('NCTF{}')
len_key = len(key)
plaintext = open('plaintext.txt', 'r').read()
plain = ''.join(p for p in plaintext if p in ascii_letters)
cipher = ''.join( itoc( ( ctoi(p) + ctoi( key[i % len_key] ) ) % 52 ) for i,p in enumerate(plain) )
open('ciphertext.txt', 'w').write(cipher)
在没有key的情况下要破解密文要经过3个阶段:
- Kasiski 实验
- 重合指数进犯
- 字母频率剖析
根据上面三个内容来进行推理，key的长度应该为8的因子，以及重合子数的运算公式，来确认密钥。解码得到密文：
vlbeunuozbpycklsjXlfpaq
LeftOrRight
标题姓名很风趣，左或则右，个人联想左子树右子树。
下载附件发现两头数据：
ascii为f09e54c1bad2x38mvyg7wzlsuhkijnop 和905e4c1fax328mdyvg7wbsuhklijznop
提示咱们要查找右边的，应该就是二叉树算法中的后序，所以咱们网上找个后序遍历的脚本去解密：
def fromFMtoL( mid ):
global las #大局后序遍历
global fir #先序遍历
root = fir[0] #取出当时树根
fir = fir[1:] #取出树根后 先序遍历把根拿出来 下面一个元素做树根
root_po = mid.find( root )
left = mid[0:root_po]
right = mid[root_po+1:len(mid)]
if len(left) > 0:
fromFMtoL( left )
if len(right) > 0:
fromFMtoL( right )
las += root
if __name__ == "__main__" :
# fir = input("先序遍历：")
# mid = input("中序遍历：")
fir = "f09e54c1bad2x38mvyg7wzlsuhkijnop"
mid = "905e4c1fax328mdyvg7wbsuhklijznop"
las = ""
fromFMtoL( mid )
print(las)
今天做的标题感觉难度很大，对于一个没有密码学根底的我来说很吃力，所以写的也不是很具体，还得继续学习啊。
